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1.用for循环实现把字符串编程Unicode码位的列表

st = '!@#$%^&*'codes = []for s in st:    codes.append(ord(s))print(codes)[33, 64, 35, 36, 37, 94, 38, 42]

2.用列表推导式实现把字符串变成Unicode码位的列表

st = '!@#$%^&*'codes = [ord(s) for s in st]priont(codes)[33, 64, 35, 36, 37, 94, 38, 42]

3.打印出两个列表的笛卡尔积

colors = ['blacks', 'white']sizes = ['s', 'M', 'L']for tshirt in ('%s %s'%(c, s) for c in colors for s in sizes):    print(tshirt)    blacks sblacks Mblacks Lwhite swhite Mwhite L    import itertoolsprint(list(itertools.product(['blacks', 'white'], ['S', 'M', 'L'])))[('blacks', 'S'), ('blacks', 'M'), ('blacks', 'L'), ('white', 'S'), ('white', 'M'), ('white', 'L')]

4.可迭代对象拆包时，怎么赋值给占位符

player_infos = [('kobe', '24'), ('james', '23'), ('Iverson', '3')]for player_names, _ in player_infos:    print(player_names)kobejamesIverson

5.Python3中用什么方法接收不确定值或参数

a, b, *c = range(8)print(a, b, c)0 1 [2, 3, 4, 5, 6, 7]a, *b, c, d = range(5)print(a,b,c,d)0 [1, 2] 3 4*a, b, c, d = range(5)print(a,b,c,d)[0, 1] 2 3 4

6.用切片将对象倒序

s = 'basketball'print(s[::-1])llabteksab

7.怎么查看列表的ID

l = [1, 2, 3]print(id(l))17159400

8.可变序列用*=（就地乘法）后，会创建新的序列吗

l = [1, 2, 3]print(id(l))28562664l *= 2print(l)[1, 2, 3, 1, 2, 3]print(id(l))28562664

9.不可变序列用*=（就地乘法）后，会创建新的序列吗

t = (1, 2, 3)print(id(t))54827560t *= 2print(t)(1, 2, 3, 1, 2, 3)print(id(t))54752040

10.关于+=的一道谜题

t = (1, 2, [30, 40])t[2] += [50, 60]print(t)(1, 2, [30, 40, 50, 60])

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